• @DoomBot5
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    81 year ago

    First one has the pitfall of a space at the end of the variable still causing it to fail.

      • @DoomBot5
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        11 year ago

        It would still be considered a single variable because the entire string is quoted. The first scenario would have split it into 2 variables.

    • @[email protected]
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      128 days ago

      I don’t think this is correct. Consider what you see from using sh -c -- 'var="a " && printf "%s\n" "${var}"-z'

      If "${var}"-z resulted in two arguments instead of one, I’d see “a” and “-z” on different lines, but I see them on the same line, which means they are treated as a single argument.