@[email protected]M to Science [email protected]English • 5 months agoI just cited myself.mander.xyzimagemessage-square225fedilinkarrow-up1825arrow-down142cross-posted to: chonglangtv
arrow-up1783arrow-down1imageI just cited myself.mander.xyz@[email protected]M to Science [email protected]English • 5 months agomessage-square225fedilinkcross-posted to: chonglangtv
minus-square@Wandering_UncertaintylinkEnglish5•5 months ago??? Not sure what you’re aiming for. It proves that the setup works, I suppose. x = 0.555… 10x = 5.555… 10x = 5 + 0.555… 10x = 5+x 9x = 5 x = 5/9 5/9 = 0.555… So it shows that this approach will indeed provide a result for x that matches what x is supposed to be. Hopefully it helped?
???
Not sure what you’re aiming for. It proves that the setup works, I suppose.
x = 0.555…
10x = 5.555…
10x = 5 + 0.555…
10x = 5+x
9x = 5
x = 5/9
5/9 = 0.555…
So it shows that this approach will indeed provide a result for x that matches what x is supposed to be.
Hopefully it helped?