I’ve got the appropriate amount of light for my microscope ring light, but now I need to put it all in an enclosure of some sort.

If I don’t have a custom board to solder these to, what are my best options for connecting these she mounting them into something?

If this is too vague, please let me know if I can clarify

    • @sneekee_snek_17OP
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      44 months ago

      I had that same thought, but I’m running 4, 3.3V diodes per parallel branch/arm/whatever, with a 12V power supply, so the calculations I’ve seen for determining the appropriate resistor tell me this doesn’t need any.

      It felt wrong, but I wanted to see if it would light up, and it did! I tried to wrap this concern into the “is it going to start on fire?” Bit lol

      • @marcos
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        44 months ago

        Not only you always need at least a resistor, but matching the power supply voltage to the leds drop will ensure you’ll have a hard time maintaining their brightness on the real world.

        If you want to keep it simple, leave 1V or 2V as a margin and add a resistor to get the desired current. If you want to make it fancy, get a led driver.

        • @sneekee_snek_17OP
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          14 months ago

          When you say “the real world” what do you mean, exactly? Because the 12V, 200mA power supply I used to power it for these pictures is likely what will ultimately power it

          • @[email protected]
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            fedilink
            24 months ago

            You have a current limiting power supply. So the power supply transistor is acting as the resistor for you in this scenario.

          • @marcos
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            4 months ago

            For example, as the leds on the original circuit age, you can expect a few of those lines to stop getting any current, and the others to get brighter and brighter until they fail.

            That can happen very quickly too, if their temperature varies a lot (how much is a lot depends on the leds). Or if you change your power supply for one capable of more current, it’s likely that everything will just fail immediately. Or, if you have a noisy one, you may severely reduce the leds lifetime.

            As a rule, you can’t use diodes internal resistance as a power limiter. It does not behave the same way as resistors and will surprise you on every bad way possible.

            • @sneekee_snek_17OP
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              14 months ago

              Huh, if I had the time I’d do some reading about it. Sounds like there’s some really interesting physics going on there

        • @sneekee_snek_17OP
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          14 months ago

          That being said, I redid it with your input in mind. It’s currently got 100U resistors and draws a good bit more than the power supply is capable of