In last round’s 15th turn, 1st place decides to hard fold upon picking a 6man by dealing a 8sou, which breaks his tenpai. Folding at this point is understandable. What I don’t understand is why he did this with a 8sou upon receiving a 6man. After all, both the 8sou and the 6man were safe against me, and neither was safe against the two other players. There wasn’t even any suji for those! So that’s my question, why did he discard the 6man and not the 8sou? Was it because the 8sou was safer against the two other players, and if so why?
The player across from them hasn’t thrown a single character tile, they could be on a half flush, full flush, pure flush, who knows. They haven’t called riichi, but they are against three open hands so maybe they’re in damaten.
The player to the right hasn’t thrown anything above 2m. They could have the red dragons and be going for a half flush too and have a dora. That’s 5 han, could be a mangan, especially if you add the extra mini points you get from a kan.
The 6m is adjacent to the new Dora, either player could have a 7778. Now it might be 8 han.
The player has a two han hand and it’s not worth pushing for and risking dealing in to some hidden monster hand. All the 9s’s are gone, they can see all the 8s’s, there’s only one live 7s. And even if they do deal in with the 8s it’s not going to be into a flush hand of some sort, maybe 2 or three han?
Thank you very much! Yep that’s crystal clear now. I completely failed to notice my own 7sou pon, that changes everything indeed.
And even without it you’re right that although 8sou would be dangerous the 6man was definitely the most dangerous due to them not having discarded any manzu!
While in this case it turned out they were actually going for a 8sou wait and not manzu, they would probably have riichi’d upon tenpai, and they would to the contrary have been more likely to be damaten in case of manzu flush. I feel like I progressed a lot with that single thread thanks to you