• @mumblerfish
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    1421 year ago

    Same trick will work next year too!

    • @[email protected]
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      1 year ago

      Brilliant, now I wonder what ages this works for, I figured only 1 and 2, but then I realised we could write the father’s age in other bases…

      1 = 2^0 (20 b10)

      2 = 2^1 (21 b10)

      3 = 3^1 (31 b7 = 22)

      6 = 6^1 (61 b4 = 25) if they are lucky the grand father will be 61 that year :-D

      8 = 2^3 (23 b12 =27)

      9 = 9^1 (91 b3 = 28)

      14 = 14^1 (141 b4 = 33)

      • aDogCalledSpot
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        11 year ago

        You have mistakes in a few of those. The number “61” doesnt exist in b4. 25b10 in b4 is “121”.

        Similar problem with 91b3 and 141b4.

        • @[email protected]
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          1 year ago

          Indeed, I was so focused on the algebraic side I didn’t even think about it :-D

          I was computing 6*4+1=25