coja to Math [email protected] • 1 year agoAccording to the statisticslemmy.mlimagemessage-square3fedilinkarrow-up150arrow-down12
arrow-up148arrow-down1imageAccording to the statisticslemmy.mlcoja to Math [email protected] • 1 year agomessage-square3fedilink
minus-square@funnystuff97link8•1 year agoNo, this is true, proof by induction: (x+y)^2 = x^2 + y^2 For (x,y) = (0,0) : (x+y)^2 = (0+0)^2 = (0)^2 = 0 x^2 + y^2 = 0^2 + 0^2 = 0 + 0 = 0 Q. E. D. Thus it should follow that it applies to every other case. (The other cases are left as an exercise for the reader.)
No, this is true, proof by induction:
(x+y)^2 = x^2 + y^2
For (x,y) = (0,0) :
(x+y)^2 = (0+0)^2 = (0)^2 = 0
x^2 + y^2 = 0^2 + 0^2 = 0 + 0 = 0
Q. E. D.
Thus it should follow that it applies to every other case. (The other cases are left as an exercise for the reader.)