• @[email protected]
    link
    fedilink
    110 months ago

    You have my interest! (Mainly because I don’t know the first thing about implementing neutral networks)

    • @[email protected]
      link
      fedilink
      English
      2
      edit-2
      10 months ago

      At the simplest, it takes in a vector of floating-point numbers, multiplies them with other similar vectors (the “weights”), sums each one, applies a RELU* the the result, and then uses those values as a vector for another layer with it’s own weights (or gives output). The magic is in the weights.

      This operation is a simple matrix-by-vector product followed by pairwise RELU, if you know what that means.

      In Haskell, something like:

      layer layerInput layerWeights = map relu $ map sum $ map (zipWith (*) layerInput) layerWeights

      foldl layer modelInput modelWeights

      Where modelWeights is [[[Float]]], and so layer has type [Float] -> [[Float]] -> [Float].

      * RELU: if i>0 then i else 0. It could also be another nonlinear function, but RELU is obviously fast and works about as well as anything else. There’s interesting theoretical work on certain really weird functions, though.


      Less simple, it might have a set pattern of zero weights which can be ignored, allowing fast implementation with a bunch of smaller vectors, or have pairwise multiplication steps, like in the Transformer. Aaand that’s about it, all the rest is stuff that was figured out by trail and error like encoding, and the math behind how to train the weights. Now you know.

      Assuming you use hex values for 32-bit weights, you could write a line with 4 no problem:

      wgt35 = [0x1234FCAB, 0x1234FCAB, 0x1234FCAB, 0x1234FCAB];

      And, you can sometimes get away with half-precision floats.

      • @[email protected]
        link
        fedilink
        110 months ago

        That’s cool, though honestly I haven’t fully understood, but that’s probably because I don’t know Haskell, that line looked like complete gibberish to me lol. At least I think I got the gist of things on a high level, I’m always curious to understand but never dare to dive deep (holds self from making deep learning joke). Much appriciated btw!

        • @[email protected]
          link
          fedilink
          English
          210 months ago

          Yeah, maybe somebody can translate for you. I considered using something else, but it was already long and I didn’t feel like writing out multiple loops.

          No worries. It’s neat how much such a comparatively simple concept can do, with enough data to work from. Circa-2010 I thought it would never work, lol.