I was wondering the same thing. I was trying to buy exactly 10 items because that’s the max they allow at the self check out now. I’m wondering if that increase the odds greatly or something.
Buying 10 items would definitely make this way more likely, because we have a base-10 counting system.
To simplify the problem, if you look at the cents digit, $0.09×10 items = $0.90. If you look at both cents digits, they were mostly $0.99. $0.99×10 items = $9.90.
All you’d need in either case there is something to cost $0.10 more to get a nice even number.
I was wondering the same thing. I was trying to buy exactly 10 items because that’s the max they allow at the self check out now. I’m wondering if that increase the odds greatly or something.
Buying 10 items would definitely make this way more likely, because we have a base-10 counting system.
To simplify the problem, if you look at the cents digit, $0.09×10 items = $0.90. If you look at both cents digits, they were mostly $0.99. $0.99×10 items = $9.90.
All you’d need in either case there is something to cost $0.10 more to get a nice even number.
If all the prices are $x.x9 then it’s only possible if you buy a multiple of 10 items.
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