In the screenshot it said x = *(++p) and iirc that is not the same as saying x = *(p++) or x = *(p += 1)
As in my example using ++p will return the new value after increment and p++ or p+=1 will return the value before the increment happens, and then increment the variable.
Or at least that is how I remember it working based on other languages.
I’m not sure what the * does, but I’m assuming it might be a pointer reference? I’ve never really learned how to code in c or c++ specifically. Though in other languages ( like PHP which is based on C ) there is a distinct difference between ++p and (p++ or p+= 1)
The last two behave the same. Though it has been years since I did a lot of coding. Which is why I asked.
I’ll install the latest PHP runtime tonight and give it a try xD
In C an assignment is an expression where the value is the new value of what was being assigned to.
In
a = b = 1
, both a and b will be 1.a = *(p = p + 1)
is the same as
p += 1 a = *p
, so ++p.
What I meant was:
In the screenshot it said
x = *(++p)
and iirc that is not the same as sayingx = *(p++)
orx = *(p += 1)
As in my example using ++p will return the new value after increment and p++ or p+=1 will return the value before the increment happens, and then increment the variable.
Or at least that is how I remember it working based on other languages.
I’m not sure what the * does, but I’m assuming it might be a pointer reference? I’ve never really learned how to code in c or c++ specifically. Though in other languages ( like PHP which is based on C ) there is a distinct difference between
++p
and (p++
orp+= 1
)The last two behave the same. Though it has been years since I did a lot of coding. Which is why I asked.
I’ll install the latest PHP runtime tonight and give it a try xD