Find ∫e^x sinx dx.
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solution
∫eˣ sin(x) dx = eˣ sin(x) - ∫eˣ cos(x) dx = eˣ sin(x) - (eˣ cos(x) + ∫eˣ sin(x) dx)
∫eˣ sin(x) dx = eˣ sin(x) - eˣ cos(x) - ∫eˣ sin(x) dx
2∫eˣ sin(x) dx = eˣ (sin(x) - cos(x)) + C
∫eˣ sin(x) dx = ½ eˣ (sin(x) - cos(x)) + C
thats it, ggs
Solutions will be out tmr, have a go on it first.[email protected] got it, congrats :D
Solution: https://gmtex.siri.sh/fs/1/School/Extra/Maths/Qotd solutions/2024-05-01_recursive-integral.html
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