https://xkcd.com/2935

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I can’t believe they wouldn’t even let me hold a vote among the passengers about whether to try the loop.

  • @[email protected]
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    91 month ago

    Holy shit I wonder if it’s even humanly possible to build one of these in the ocean for any size ship.

      • @Dozzi92
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        51 month ago

        Cruise ship or bust.

        And it’s just a drawing but I’m trying to realize it in actual size. Cruise ships are huge, pushing 250 or so feet out of the water. That’s considered a high-rise in the construction world.

        Now I look at that loopdy-lopp and say hey, that boat could fit. I’m ignoring all the other physics and shit and just Matchbox car’g that boat through that loop. That makes that loop like, what, 1000 feet? And that is ignoring the structure beneath the surface, and also the other dimensions of this, and the sheer velocity and volume of water.

        So I’m gonna call this one a hard maybe. Perhaps if the world could set aside it’s differences, we could do a sort of space race, but instead a ship flip, or a boat float, or some other rhyme.

        • @[email protected]
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          51 month ago

          sounds like an idea for a “what if” scenario. I know just the author to pitch this to…

    • @[email protected]
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      430 days ago

      You just have to go fast enough. The minimum speed keeping you from falling out of a circular loop is sqrt(gr), with gravitational acceleration g and loop radius r. 10m radius requires 36km/h, which might be suitable for a Jetski. Larger ships need bigger loops to physically fit, and consequently larger speeds. It’s quite surprising, but a monstrous 100m radius loop needs less than 120km/h.

      • @[email protected]
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        129 days ago

        so mass doesn’t factor into the equation??? a Jetski made from aluminum would need the same speed as from osmium?

        • @[email protected]
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          129 days ago

          I think so. At the apex of the loop gravity balances centrifugal force, Fg = Fc, when going the minimal speed necessary to get through the loop. Fg = m g, Fc = m v^2 / r. So mass m drops out of the equation.