• @[email protected]
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    55 months ago

    Should be anything less than a harmonic decrease (that is, the nth centaur is 1/n the size of the original).

    The harmonic series is the slowest-diverging series.

    • Kogasa
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      15 months ago

      The assumption is that the size decreases geometrically, which is reasonable for this kind of self similarity. You can’t just say “less than harmonic” though, I mean 1/(2n) is “slower”.

        • Kogasa
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          25 months ago

          Yes, but it proves that termwise comparison with the harmonic series isn’t sufficient to tell if a series diverges.