sagM to [email protected] • 5 months agotwelverabbits was right!files.catbox.moeimagemessage-square3fedilinkarrow-up116arrow-down15file-text
arrow-up111arrow-down1imagetwelverabbits was right!files.catbox.moesagM to [email protected] • 5 months agomessage-square3fedilinkfile-text
minus-square@bisbylinkEnglish2•5 months agoLooks like n of a kind results in (n^2-n)/2 pairs. (Which is the same as the sum of 1…(n-1)) 5 of a kind would be 10 pairs. 6 of a kind would be 15, etc
Looks like n of a kind results in (n^2-n)/2 pairs. (Which is the same as the sum of 1…(n-1))
5 of a kind would be 10 pairs. 6 of a kind would be 15, etc