This all hinges on when you count the number of problems you have. But that’s why you have two eyes! Read the same page of books 1 and 2 in parallel and obliterate 100% of your problems.
I disagree. If one book solves half of your problems at random and the other does the same, that’s still 75% on average, and 25% on average will have 2 solutions.
No you can solve 3/4ths of your problems
Zeno’s problem.
Would that make Zeno’s Wank just a type of edging?
Yes.
if you learn how to solve zeno’s problem in the first book, it may be possible to solve 100% of your problems in the second book
If you buy 5 books, you’ll be able to solve 96.88% of your problems.
Or you could just read the one book eight times for 99.6℅. Why buy more than one when one is enough to read as many times as you like?
that’s some mighty fine fiscal responsibility, right there
Well guess what? That was an e-book and you only get to read once.
This all hinges on when you count the number of problems you have. But that’s why you have two eyes! Read the same page of books 1 and 2 in parallel and obliterate 100% of your problems.
I disagree. If one book solves half of your problems at random and the other does the same, that’s still 75% on average, and 25% on average will have 2 solutions.