I am really trying not to guess, but have been stumped for a while here. I have cleared out a few impossible, but they weren’t enough. Anyone can explain the next move?

EDIT: solved below!

  • SeefooOP
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    2 months ago

    They are not all In the same column, so you can’t eliminate it.

    • elbucho
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      2 months ago

      There are definitely 3 squares in the last column that can only be 1, 6, or 8, with no other possibilities: R1C9, R5C9, R6C9. That means that R2C9 and R3C9 can’t include a 1, 6, or an 8.

      Additionally, your 3s are confined to columns 7 and 8 in boxes 6 and 9, which means that you can’t possibly have a 3 in R2C8. This makes R2C9 a 3, and therefore R3C9 a 5.

      Making these moves opens a few other moves up in the board.

      • SeefooOP
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        2 months ago

        Ahh I follow that now! Thanks, this unlocked the rest