to my knowledge, if you input any text it will return true and if you input nothing it will return false. if it’s possible without if statements, how do i check if they inputted ‘True’ or 'False (/ ‘1’ or ‘0’) when im doing ‘bool(input("Input True or False ")’.
Without if statements?
Apologies typing on my phone
def input_checker(input_str):
You are comparing the content of strings, not their truth value. A string is true if it’s not empty and false if it is. The string “True” is no closer to the bool True than the string “Oranges” is.
What you are looking for is input validation. Check the content of what they wrote and respond accordingly.
why is my input being seen as a string in the firsr place if i typecasted the variable as a boolean? how do i make the input itself a bool (rather than the variable?)
User inputs are strings, which can be anything. You are hoping they input True or false but what if they input tRUe or FALSE77 or Hunter4 or jgidqopqncb uriwnsvsveyqiaoNcbtjwnak? bool(“tRUe”) doesn’t evaluate to True or False in the way you think it does.
If you want to convert user input to a bool use a lookup dict with some validation rules (like lower casing input text) to sanitize the input. I cannot emphasize this enough - never trust user input.
Always trust user input’); DROP TABLE users;
Worth remembering that python uses the concepts of truthy and falsey. Empty string (“”) is falsey. Any other string (“true”, “false”, “0”, etc.) Is truthy. All bool(str) does is evaluate whether str is truthy or falsey. It does not evaluate what str actually is.
So bool(input("Input True or False ") will return False is the user input is empty and True otherwise.
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You can use eval(input). It converts string to whatever the actual content is.
Which is really bad if the user inputs executable code. Never call eval on unsanitized text
wait so eval(bool(input(‘Input:’)
Yeah, don’t do that. Users could accidentally or maliciously type something that would get executed as python code and break your program