Thanks Homer.

  • @[email protected]
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    fedilink
    21 year ago

    Hmm, I did it the opposite. Found every number and passed a list of every adjacent position of the number to check for non-digit/dot/non-whitespace.

    Took a bit longer to solve part 2 due to that approach though.

    • Black616Angel
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      fedilink
      11 year ago

      In that case I was kinda lucky.

      But it looked more second-partly to do it that way. 😂