@[email protected]M to [email protected]English • 1 year agosoak and jump humpfeddit.deimagemessage-square120fedilinkarrow-up1796arrow-down124
arrow-up1772arrow-down1imagesoak and jump humpfeddit.de@[email protected]M to [email protected]English • 1 year agomessage-square120fedilink
minus-squareNoIWontPickaNamelinkfedilink9•1 year agoI can’t tell if that is a purposeful typo or not.
minus-square@[email protected]linkfedilink4•1 year agoA word isn’t a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B)
minus-square@themusicmanlink1•edit-21 year agoIf words are an ordered set, then mormon = morn Words are a base 27 integer. (mormon - mon) / a000 + on = moron
minus-squareRustmilianlinkEnglish7•edit-21 year agoWindows user detected. You’re so case-insensitive, ba-dum-tss.
minus-square@[email protected]linkfedilinkEnglish4•1 year agothe remainder n needs to be accounted for
minus-square@[email protected]linkfedilink3•1 year agoThe n stands for nothing, therefore it’s invisible.
Mormon - m = Moron
Mormon - m = Oro
Did you mean oron?
I can’t tell if that is a purposeful typo or not.
mormon - 5*n = Oro
Technically it’d need to be:
mormon / 2m = oron
A word isn’t a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B)
You’re right, that would be more technically correct.
If words are an ordered set, then mormon = morn
Words are a base 27 integer. (mormon - mon) / a000 + on = moron
Perhaps…
Mormon - m + e = oreo
Windows user detected.
You’re so
case-insensitive, ba-dum-tss.Oro+a-o= ORA ORA ORA ORA ORA!!!
the remainder n needs to be accounted for
The n stands for nothing, therefore it’s invisible.
deleted by creator
Math ✔️’s out.
Mormon - m = m (Moron - 1)
Or… ormon… oron