Day 7: Camel Cards

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  • @[email protected]
    link
    fedilink
    2
    edit-2
    1 year ago

    Crystal

    got stuck on both parts due to silly mistakes.
    On the other hand I’m no longer behind!

    code
    input = File.read("input.txt").lines
    rank = {
    	'J' => 1,
    	'2' => 2,
    	'3' => 3,
    	'4' => 4,
    	'5' => 5,
    	'6' => 6,
    	'7' => 7,
    	'8' => 8,	
    	'9' => 9,
    	'T' => 10,
    	# 'J' => 11,
    	'Q' => 12,
    	'K' => 13,
    	'A' => 14
    }
    
    hand = input.map do |line|
    	split = line.split
    	weights = split[0].chars.map {|c| rank[c]}
    	{weights, split[1].to_i}
    end
    
    hand.sort! do |a, b|
    	a_rank = get_rank(a[0], true)
    	b_rank = get_rank(b[0], true)
    	
    	# puts "#{a}-#{a_rank} #{b}-#{b_rank}"
    	next  1 if a_rank > b_rank
    	next -1 if b_rank > a_rank
    
    	val = 0
    	5.times do |i| 
    		val =  1 if a[0][i] > b[0][i]
    		val = -1 if b[0][i] > a[0][i]
    		break unless val == 0
    	end
    	val
    end
    
    sum = 0
    hand.each_with_index do |card, i|
    	sum += card[1]*(i+1)
    end
    puts sum
    
    
    def get_rank(card : Array(Int32), joker = false ) : Float64 | Int32
    	aa = card.uniq
    
    	if joker
    		card = aa.map { |c|
    			combo = card.map {|a| a == 1 ? c : a }
    			{combo, get_rank(combo)}
    		}.max_by {|a| a[1]}[0]
    		aa = card.uniq
    	end
    	
    	rank = 6 - aa.size
    	case rank
    	when 3
    		return 3.5 if card.count(aa[0]) == 3
    		return 3   if card.count(aa[0]) == 2
    		return 3   if card.count(aa[1]) == 2
    		return 3.5
    	when 4
    		return 4 if card.count(aa[0]) == 3 || card.count(aa[0]) == 2
    		return 4.5
    	else 
    		return rank
    	end
    end