Because if you search Firefox and see a badge that says verified, you can be confident that it was Mozilla that packaged it and added it to FlatHub as opposed to some random scammer.
Verification doesnt help at all if the source is not trusted. All this says is “upstream developers maintain this package”. Unofficial packages can be safe too, like VLC.
It does help prevent actual malware from being downloaded, though, since upstream developers probably won’t publish malware on Flathub.
But this is still a half-measure. I don’t understand why Red Hat and Canonical don’t treat this issue seriously; people on Linux are used to assuming software installed from the repos are safe, and yet Snap and Flatpak are being pushed more and more despite their main repositories being potentially unsafe.
I can’t find it now, but I read that the verification process also includes human review (for the initial verification, not every update), so it should actually prevent “verified” malware (though it does nothing against unverified malware).
Because both Red Hat and Canonical are of the “pay us to care” mindset. If you aren’t paying for support, you’re a freeloader and need to do your own research.
That’s not entirely true with Red Hat. There’s a lot of work that they’ve done in the open source community that they haven’t shared back. And canonical seems to think this is a good idea.
Nice
Good to see one of the two big packaging hubs do something against malware
How does that Help against Malware?
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Because if you search Firefox and see a badge that says verified, you can be confident that it was Mozilla that packaged it and added it to FlatHub as opposed to some random scammer.
You can’t just upload a App to Flathub. Everythng is reviewed.
Things get missed. And they don’t get reviewed in every update, just the original upload.
Apt has done this forever
Verification doesnt help at all if the source is not trusted. All this says is “upstream developers maintain this package”. Unofficial packages can be safe too, like VLC.
It does help prevent actual malware from being downloaded, though, since upstream developers probably won’t publish malware on Flathub.
But this is still a half-measure. I don’t understand why Red Hat and Canonical don’t treat this issue seriously; people on Linux are used to assuming software installed from the repos are safe, and yet Snap and Flatpak are being pushed more and more despite their main repositories being potentially unsafe.
Flathub is doing more and more, but stuff like hiding
--subset=verified
is very bad.They simply need to gain critical mass until they can force changes like portals etc.
If you create malware and publish it on flathub, you are the upstream dev. But for sure it helps against duplicate scams.
I can’t find it now, but I read that the verification process also includes human review (for the initial verification, not every update), so it should actually prevent “verified” malware (though it does nothing against unverified malware).
Edit: Here’s an article with this and more info: https://lwn.net/SubscriberLink/966187/3ef48792e5e8c71d/
Nice!
Add flathub with
--subset=verified
and get apps you really need from their .flatpakref filesFedora has their own flatpak repo built from their own rpms and their own runtime. Flathub has more flatpaks though.
Because both Red Hat and Canonical are of the “pay us to care” mindset. If you aren’t paying for support, you’re a freeloader and need to do your own research.
I mean, that’s pretty much all open source software and isn’t specific at all to RH/Canonical.
What’s provided to you is provided without warranty and you’re not automatically entitled to support, etc.
That’s not entirely true with Red Hat. There’s a lot of work that they’ve done in the open source community that they haven’t shared back. And canonical seems to think this is a good idea.
I’m not really sure what you mean by that. What do you mean they’ve done a lot of work for the open source community that they haven’t shared back?
And what does it have to do with providing software support free of charge?