Interesting. Given that H• is a neutral species, what would cause the preference for the creation of stable negative species (freeing up H+) over the creation of stable positive species (freeing up OH-)?
Neutral as far as pH is concerned, yes. However, radicals tend to be very reactive due to their valance not being full. I am a bit rusty, TBH, as I’m about a decade and a half out of uni but, the best way to predict the products of the reaction is to look at the high-level of the equation:
All of the products of the initial reaction here are radicals except for the H2 molecules. They all are going to further react to form more stable species with full valances, with possible exception being the molecular hydrogen. Because the elemental hydrogen is introduced as a radical rather than protons (H+ ions) in the solution, the final products are likely to be more negatively charged, neutral, and/or have some interesting hydrogen additions, especially in the hydrocarbons and amino acids.
For example, there could be reactions like:
R• + •OH + •N-R -> R-OH + HO-N-R
Overall, however, the amount of free hydrogen/protons is likely to be reduced as they are effectively removed from solution as hydrogen gas.
Because the elemental hydrogen is introduced as a radical rather than protons (H+ ions) in the solution, the final products are likely to be more negatively charged
This is the part I don’t understand. If charge is conserved, why would there be a preference for a particular charge in the products?
No. I think that you’re absolutely correct. The products should have charge conserved. After initial attack of hydrocarbons by H• radicals, H2 is likely to be a significant product. Supposing STP, it would likely remove itself from solution, leaving the fresh radicals to chain react and probably making interesting and unhealthy things.
My apologies, I’m out of the lab and field 15 years now so, do make some pretty basic mistakes at times.
After initial attack of hydrocarbons by H• radicals, H2 is likely to be a significant product. Supposing STP, it would likely remove itself from solution, leaving the fresh radicals to chain react and probably making interesting and unhealthy things.
That makes sense.
My apologies, I’m out of the lab and field 15 years now so, do make some pretty basic mistakes at times.
Interesting. Given that H• is a neutral species, what would cause the preference for the creation of stable negative species (freeing up H+) over the creation of stable positive species (freeing up OH-)?
Neutral as far as pH is concerned, yes. However, radicals tend to be very reactive due to their valance not being full. I am a bit rusty, TBH, as I’m about a decade and a half out of uni but, the best way to predict the products of the reaction is to look at the high-level of the equation:
H• (excess) + H••OH + H••R + H••N-R -> H2(g) + •OH + •R + •N-RAll of the products of the initial reaction here are radicals except for the H2 molecules. They all are going to further react to form more stable species with full valances, with possible exception being the molecular hydrogen. Because the elemental hydrogen is introduced as a radical rather than protons (H+ ions) in the solution, the final products are likely to be more negatively charged, neutral, and/or have some interesting hydrogen additions, especially in the hydrocarbons and amino acids.
For example, there could be reactions like:
R• + •OH + •N-R -> R-OH + HO-N-ROverall, however, the amount of free hydrogen/protons is likely to be reduced as they are effectively removed from solution as hydrogen gas.
This is the part I don’t understand. If charge is conserved, why would there be a preference for a particular charge in the products?
No. I think that you’re absolutely correct. The products should have charge conserved. After initial attack of hydrocarbons by H• radicals, H2 is likely to be a significant product. Supposing STP, it would likely remove itself from solution, leaving the fresh radicals to chain react and probably making interesting and unhealthy things.
My apologies, I’m out of the lab and field 15 years now so, do make some pretty basic mistakes at times.
That makes sense.
No worries! I’ve enjoyed this discussion!