• @TIMMAY
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    566 months ago

    I remember learning this out of curiosity in the past, but math doesnt stick in my brain unless chemistry is used as a disguise. Where can I read about this method again? Will the wiki page on Gauss get me there efficiently enough?

    • @[email protected]
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      306 months ago

      you’ll either get there, or to the Boston Molasses Disaster, so you’ll learn something cool either way.

      • @TIMMAY
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        56 months ago

        I know about this one! I think it was a Reactions video, which I believe is the American Chemical Society’s yt channel

      • @acetanilide
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        66 months ago

        Just wanted to say thanks! Clicking your link made me realize I should try to figure out how to open up YT on PipePipe automatically, so now my phone works better :)

        • @SzethFriendOfNimi
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          26 months ago

          No problem. I have a script that automates generating the title and link to a video when sharing automatically.

          I should look into having it do the same for pipe

      • Deebster
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        26 months ago

        So was he writing backwards, or did they print a custom flipped t-shirt?

        • @SzethFriendOfNimi
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          16 months ago

          I’ve always wondered how they do that. Because writing backwards would feel so weird to me

    • @[email protected]
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      6 months ago

      The sum of all natural numbers smaller than and including x is equal to

      (x+1)(x/2)

      The sum of all even numbers up to and including x is that minus (n/2)² so

      [(x+1)(x/2)]-(x/2)²

      That would mean the sum of all odd numbers under x is equal to

      (x/2)²

      or sum of all odd including x (if x is odd of course) is

      [(x+1)/2]²

      Since the sum of all even numbers up to x is the sum of all numbers minus the sum of all odd numbers.

      [-(x/2)² +2x +1]/2 (another way of writing the sum of all evens under and including a number) looks suspiciously polynomial. I want to go further.

      Edit:

      Interestingly, the sum of all evens under and including x is larger than the sum of all odds under x by half of x. So

      [(x+1)(x/2)-(x/2)²]-(x/2) = (x/2)²

      So another formula for sum of all evens is

      (x/2)²+(x/2)

      So,

      2[(x/2)²]+(x/2) = (x+1)(x/2)

      The left is the sum of all odds plus the sum of all evens under and including x, the right is the original formula we started with, sum of all natural numbers under and including x. Since they both give us the total sum for all natural numbers up to and including x, the left hand side is a different formula giving us the same result!