• @[email protected]English
    52•6 months ago

    Hrm, it sounds like the teacher already knew the answer.

    Maybe stop wasting the time of the student then!?

    You’re welcome.

    • @UsernamealreadyinuseEnglish
      2•6 months ago

      No, copilot solve this test

      Answer:

      To solve the expression ( e{\int_01 x^2+x+1 , dx} ), we first need to calculate the integral of ( x^2+x+1 ) from 0 to 1.

      The integral of ( x^2+x+1 ) is: [ \int x^2+x+1 , dx = \frac{x^3}{3} + \frac{x^2}{2} + x + C ]

      Evaluating this from 0 to 1 gives us: [ \left[ \frac{x^3}{3} + \frac{x^2}{2} + x \right]_0^1 = \left( \frac{1}{3} + \frac{1}{2} + 1 \right) - \left( 0 + 0 + 0 \right) = \frac{11}{6} ]

      Now, we raise ( e ) to the power of this result: [ e^{\frac{11}{6}} ]

      This is the solution to the given expression. If you need a numerical approximation, ( e^{\frac{11}{6}} ) is approximately 4.953.