Day 2: Cube Conundrum


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FAQ


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  • @mykl
    link
    41 year ago

    I had some time, so here’s a terrible solution in Uiua (Run it here) :

    Lim ← [14 13 12]
    {"Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green"
     "Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue"
     "Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red"
     "Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red"
     "Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green"}
    
    LtoDec ← ∧(+ ×10:) :0
    StoDec ← LtoDec▽≥0. ▽≤9. -@0
    FilterMax! ← /↥≡(StoDec⊢↙ ¯1)⊔⊏⊚≡(/×^1⊢).⊔
    # Build 'map' of draws for each game
    ∵(□≡(∵(⬚@\s↙2 ⊔) ⇌) ↯¯1_2 ↘ 2⊜□≠@\s . ⊔)
    # Only need the max for each colour
    ≡(⊂⊂⊃⊃(FilterMax!(="bl")) (FilterMax!(="gr")) (FilterMax!(="re")))
    # part 1 - Compare against limits, and sum game numbers
    /+▽:+1⇡⧻. ≡(/×≤0-Lim).
    # part 2 - Multiply the maxes in each game and then sum.
    /+/×⍉: