You know this would be a great programming problem for CS students. Given the phrase “head less horse man”, generate all 4-word phrases, repeated words allowed. (Some of the ones in this picture aren’t 4 words, but anyways…)
Consider the words “head less horse man” to be digits in a base-4 number system; head=0 less=1 horse=2 man=3. Counting from 0 to (4^4)-1 would yield 256 unique values,
- head head head head = 0
- head head head less = 1
- head head head horse = 2
- head head head man = 3
- head head less head = 10 (4 base 10)
- …
- man man man man = (4^4)-1 = 3333 (255 base 10)
Bonus points for funniest picture to go with a value (must be hand-drawn by student, no AI allowed) :)
EDIT: not permutations, which I originally said. It’s more of an exercise in understanding how to count in bases other than 10.
no horseless headless horseman?
I don’t know why the Manhorse bothers me so much that it’s not a centaur…
Meanwhile horseman…
Maybe he’s born with it…maybe it’s neighbelline?
That joke is so dead that you’re breaking a sweat flailing away at it.
Nah he’s just BoJack Horseman
is that… the beatles?
Missed opportunity: “maneless horse” and “horseless mane”
The meme forgot Centaur and Wrong Half
NGL goes hard
