cross-posted from: https://infosec.pub/post/789102

As Italy swelters under dangerous heat, McDonald’s workers called a strike after their air conditioning broke in oppressively hot kitchens.

  • @[email protected]
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    752 years ago

    Thanks. Whenever I see Fahrenheit units I have no fucking idea of what the actual temperature is meant to be

    • SteefLem
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      642 years ago

      Yeah i know what u mean, and since the article is about italie which uses celcius its even weirder :)

    • PaleRider
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      2 years ago

      So the proper conversion from Celsius to Fahrenheit is F = 9/5C + 32

      But an easy way to do it (roughly) from Celsius to Fahrenheit is double it and add 30.

      To convert from Fahrenheit to Celsius is subtract 30 then halve it.

    • I_Miss_Daniel
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      92 years ago

      One helpful tip I’ve figured out. 100 foreignheight is body temperature. So if it’s around 100°F it’s around 38°C.

    • @[email protected]
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      2 years ago

      I think about the difference between the two using differences instead of absolutes. That looks like this:

      It’s kind of hard to do this calc:

      F = [ (9/5) * C ] + 32

      Or this one:

      C = (5/9) * (F - 32)

      I refer to those as absolute equations. You have to take into account the pesky offset everytime you want to convert. What if we drop it? This makes:

      F = (9/5) * C = 1.8 * C

      C = (5/9) * F ~= 0.6 * F

      I refer to those as relative or difference equations because if you subtract a temperature from the other, you get the same thing:

      F1 = [ (9/5) * C1 ] + 32

      F2 = [ (9/5) * C2 ] + 32

      F2 - F1 = [ (9/5) * C2 ] + 32 - { [ (9/5) * C1 ] + 32 }

      = [ (9/5) * C2 ] - [ (9/5) * C1 ] + 32 - 32

      = [ (9/5) * C2 ] - [ (9/5) * C1 ]

      = (9/5) [ C2 - C1 ]

      F2 - F1 = (9/5) (C2 - C1)

      ∆F = (9/5) ∆C

      So, why is this useful?

      Say you have a temperature in Celsius and want to go to Fahrenheit. Simply multiply that number in your head by 1.8 (or think of this as multiplying by 180° as in trig) and finally add to 32. So, 1 °C is (1 * 1.8) + 32 °F or about 34 °F.

      Going the other way is a little bit weirder. I make approximations when going the other way by thinking of 180° and how that can be divided. So, 180°, 90°, 45°, etc. corresponds to 1.8 °F (1 °C), 0.9 (0.5 °C), 0.45 °F (0.25 °C), etc. I also approximate by choosing the nearest multiple of 5 or 10 °C (9 or 18 °F). So, 44 °F is between 41 °F (5 °C) and 50 °F (10 °C), closer to 41. It’s off by 3, which is about 3.6, which is 2 in Celsius world. This means 44 °F is about 7 °C.

      Hope you get the gist! Celsius really is better. I remember this in a pinch:

      10 °C = 50 °F

      20 °C = 68 °F

      30 °C = 86 °F

      40 °C = 104 °F

      50 °C = 122 °F

      Etc.

      The freezing temps are a little hard since you cross zero into negatives, but the extrapolation can help

    • @[email protected]
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      32 years ago

      A little helper to get a feel for it: 20°C is 68°F, 25°C is 77°F, 30°C is 86°F etc. Meaning, you just remember one or two combinations and then for every 5°C change it’s 9°F up or down

      • @FireRetardant
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        232 years ago

        Or America could stop pretending to be special and just use the metric system.

        • @ilickfrogs
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          112 years ago

          Right? You’d swear they invented the imperial system the way they latch on to it. Fucking ridiculous.

          • @FireRetardant
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            82 years ago

            I feel bad for american youth struggling in math and sciences. The imperial system has so much less connectivity between their units that the only way is to memorize all sorts of arbitrary numbers.

      • SteefLem
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        172 years ago

        Yeah this really not helping, me at least :)

      • @VaidenKelsier
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        12 years ago

        This has been the most singularly useful tip in trying to equate F to C. Thanks!