• @Zehzin
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    5 months ago

    You got nothing on the 17 square packing

          • @[email protected]
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            35 months ago

            No, suffering would be if it were always the same predictable pattern in everything all the time.

            • Colonel Panic
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              45 months ago

              True. You can’t have joy without suffering, light without dark, cars without an extended warranty.

          • @MisterFrog
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            35 months ago

            If God was real / or is real and cared, we would have a perfect 336 day year.

            • Colonel Panic
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              15 months ago

              If God was real the boxes would all fit in a nice grid for any square container. But the OP already has the conclusion for that one.

        • @[email protected]
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          85 months ago

          Thanks I’ve lost 30 sanity points now, and I’m now sure with a number of squares sufficently high s is gonna equal to cthulu.

      • @[email protected]
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        345 months ago

        We’ve figured out optimal packing methods for any number of squares inside a big square. When a number is below and near a square number like 15, you just leave an empty box, but when it’s far from the next square number, you’ll be able to pack them more efficiently than just leaving empty squares around. Turns out this kind of stuff is hilariously hard to prove that it’s the most efficient method.

    • Zagorath
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      545 months ago

      This is about the most efficient way to pack that number of circles. By looking at the bottom row of the 49, you can see that it’s slightly less wide than 7 diameters, because it has 5 circles at the very bottom (taking up 5 diameters of width), but two are slightly raised, which also means they’re slightly inward.

  • @datelmd5sum
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    5 months ago

    I mean it makes sense when you think about how the circles arrange in an infinte square and e.g. 4r square. There has to be some fuckery between the perfect packing and the small square packing. You can see a triangle of almost perfect packing in the middle of the 49 circle square, surrounded by fault lines in the structure and then some more good packing, and garbage in the bottom.

    slightly related Steve Mould video

    • @Maggoty
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      35 months ago

      Or, they could do 6x8 with one obviously extra at the end. But this is a funny not a rational thing.

    • @[email protected]
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      15 months ago

      Well-put. One perfect pattern at one scale, another perfect pattern at a different scale, and then there has to be a transition between them of optimal steps along the way. I like that.

  • @[email protected]
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    5 months ago

    How?

    Yes, if you push the circles down a bit, it forms a 7 by 7 matrix. But if pushing the circles into a square matrix is not allowed: how?

    Edit: I get it now. It is about (efficient) packing not about counting. I also get the 4th panel now…

      • @[email protected]
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        5 months ago

        Thanks. I thought it was about counting. It all makes a lot more sense now. (And it also doesn’t.)

    • @[email protected]
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      5 months ago

      Yeah it can fit almost 7 in a line in the last panel so theese definitely aren’t the same squares(or circles)

  • VeganPizza69 Ⓥ
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    5 months ago

    This is the kind of stuff the timber mafia needs to know so that they can efficiently pack trees and send them to IKEA.

    • enkers
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      25 months ago

      I think you skipped a row.

      Also, 6*6+7=???

      • @[email protected]
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        95 months ago

        I did yeah; deleted my content almost immediately after posting it because I went to double check. Counting is hard!

    • enkers
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      5 months ago

      Because it’s a smaller area than 7x7.

      If you consider the regular packing in an infinite plane, tri/hex packing is the most space efficient (least wasted space), so I’d assume larger packings would tend towards that. But in smaller packings, the efficiency loss from the extra size needed to offset the circles outweighs the efficiency gained by hex packing.

      7x7 is the boundary where those efficiency tradeoffs switch.

      • ddh
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        15 months ago

        Trying to think how tri/hex is more efficient than any regular tiling, say squares.

        • enkers
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          5 months ago

          Want a hint? Think about a circle bound by an n-sided polygon. What happens to the space between the bounding polygon and the circle as n increases? And when n is infinite?

          So of three possible regular tilings, which will be most and least efficient?

          (Btw, strictly speaking, I shouldn’t have said tri/hex before, as it’s really just hex tiling.)

          You could also use some fancy trig to calculate the efficiency %, but that’s way too much work for me. :)

  • @Kayday
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    5 months ago

    deleted by creator